JEE PHYSICS MCQ: MOTION IN PLANE

1 Hard

1 of 1

Analyzing +4 | -1

Let the cosine of angle between the vectors

\mathbf{p}

and

\mathbf{q}

\lambda

such that

2 \mathbf{p}+\mathbf{q}=\hat{\mathbf{i}}+\hat{\mathbf{j}}

and

\mathbf{p}+2 \mathbf{q}=\hat{\mathbf{i}}-\hat{\mathbf{j}}

, then

\lambda

is equal to

View answer and explanation

Correct option: B

-\frac{4}{5}

Option B (

-\frac{4}{5}

) is correct because by solving for vectors

\mathbf{p}

and

\mathbf{q}

and then using the cosine formula, we find the cosine of the angle between them.

More Questions from MOTION IN PLANE

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\mathrm{\vec P} = \mathrm{\vec A} + \mathrm{\vec B}\,\,\mathrm{and}\,P = A + B.

\mathrm{\vec A}\,and\,\mathrm{\vec B}

0^{\circ}

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\mathrm{If}\,(\mathbf{a}+3 \mathbf{b}) \cdot(7 \mathbf{a}-5 \mathbf{b})=0

(\mathbf{a}-4 \mathbf{b}) \cdot(7 \mathbf{a}-2 \mathbf{b})=0

\mathbf{a}

\mathbf{b}

\theta

\left(90^{\circ}-\theta\right)

39.2 \mathrm{~ms}^{-1}

50 \mathrm{~m}

{g}=9.8 \mathrm{~ms}^{-2}