JEE PHYSICS MCQ: THERMODYNAMICS

1 Medium

1 of 1

Application +4 | -1

A carnot engine takes 300 calories of heat from a source of 500 K and rejects 150 calories of heat to the sink. The temperature of the sink is

View answer and explanation

Correct option: B

250 K

Option B (250 K) is correct because it is calculated using the Carnot engine efficiency formula relating heat and temperature.

More Questions from THERMODYNAMICS

Practice All Chapter MCQs →

0.25\,\,{m^3}

{10^3}N/{m^2},

T

P

V

\left( {\gamma = \frac{{{C_p}}}{{{C_v}}}} \right)