The value of $\mathop {\lim }\limits_{x \to \infty } {\left( {\frac{{x + 3}}{{x + 1}}} \right)^{x + 2}}$ is

JEE MATHEMATICS MCQ: LIMITS

1 Easy

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Application +4 | -1

The value of

\lim\limits_{x \to \infty } {\left( {\frac{{x + 3}}{{x + 1}}} \right)^{x + 2}}

View answer and explanation

Correct option: C

{e^2}

Option C (

{e^2}

) is correct because the limit can be rewritten in the form

\lim_{x \to \infty} (1 + \frac{a}{x})^x = e^a

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