Electrolysis of $X$ gives $Y$ at anode. Vacuum distillation of $Y$ gives ${{\rm{H}}_2}{{\rm{O}}_2}$. The number of peroxy (O - O) bonds present in $X$ and $Y$ respectively are

JEE CHEMISTRY MCQ: HYDROGEN

1 Medium

1 of 1

Analyzing +4 | -1

Electrolysis of

X

gives

Y

at anode. Vacuum distillation of

Y

gives

{\mathrm{H}_2}{\mathrm{O}_2}

. The number of peroxy (O - O) bonds present in

X

and

Y

respectively are

View answer and explanation

Correct option: C

Zero, 1

The correct answer is C because sulfuric acid (X) has no peroxy bonds, and perdisulfuric acid (Y) has one peroxy bond.