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JEE MATHEMATICS MCQ: LIMITS

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Analyzing +4 | -1
lim⁡n→∞(1+1n2)8n3πsin⁡(π2n)\lim \limits_{{n \rightarrow \infty}}\left(1+\frac{1}{n^2}\right)^{\frac{8 n^3}{\pi} \sin \left(\frac{\pi}{2 n}\right)} is equal to
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Correct option: B
e4e^4
Option B (e4e^4) is correct because by manipulating the limit into the form of ee, the expression simplifies to e4e^4.

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