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JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

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Application +4 | -1
If the sum of the greatest integer less than or equal to xx and the least integer greater than or equal to xx is 5, then the solution set for xx is
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Correct option: A
(2,3)\left( {2,3} \right)
Option A ((2,3)\left( {2,3} \right)) is correct because the sum of the greatest integer less than or equal to xx and the least integer greater than or equal to xx is 5 only when 2<x<32 < x < 3.

More Questions from QUADRATIC EQUATIONS

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The solution of the equation log⁑7log⁑5(x+5+x)=0\log _7 \log _5(\sqrt{x+5}+\sqrt{x})=0 is If Ξ±,Ξ²\alpha ,\beta are the roots of x2βˆ’3x+a=0,a∈R{x^2} - 3x + a = 0,a \in R and Ξ±<1<Ξ²,\alpha < 1 < \beta , then If Ξ±,β€…β€ŠΞ²\alpha ,\;\beta be the roots of the equation x2βˆ’px+q=0{x^2} - px + q = 0 and Ξ±1,Ξ²1{\alpha _1},{\beta _1} be the roots of the equation x2βˆ’qx+p=0,{x^2} - qx + p = 0, then the equation whose roots are 1Ξ±1Ξ²+1Ξ±Ξ²1andβ€…β€Š1Ξ±Ξ±1+1Ξ²Ξ²1,\frac{1}{{{\alpha _1}\beta }} + \frac{1}{{\alpha {\beta _1}}}\mathrm{and}\;\frac{1}{{\alpha {\alpha _1}}} + \frac{1}{{\beta {\beta _1}}}, is If x2+4ax+2>0{x^2} + 4ax + 2 > 0 for all values of xx, then aa lies in the interval If f(x)=ax2+bx+cβ€…β€Šf\left( x \right) = a{x^2} + bx + c\; and β€…β€Šf(βˆ’1)<1,f(1)>βˆ’1,f(3)<βˆ’4β€…β€Š\;f\left( { - 1} \right) < 1,f\left( 1 \right) > - 1,f\left( 3 \right) < - 4\; and β€…β€Šaβ‰ 0,\;a \ne 0, then Root(s) of the equation 9x2βˆ’18∣x∣+5=09{x^2} - 18\left| x \right| + 5 = 0 belonging to the domain of definition of the function f(x)=log⁑(x2βˆ’xβˆ’2)f\left( x \right) = \log \left( {{x^2} - x - 2} \right) is (are)
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