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JEE CHEMISTRY MCQ: ALCOHOLS & PHENOLS & ETHERS

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Analyzing +4 | -1
An alcohol on oxidation is found to give CH3COOHC{H_3}COOH and CH3CH2COOHC{H_3}C{H_2}COOH The alcohol is:
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Correct option: D
CH3CH(OH)CH2CH2CH3C{H_3}CH(OH)C{H_2}C{H_2}C{H_3}
Option D (CH3CH(OH)CH2CH2CH3C{H_3}CH(OH)C{H_2}C{H_2}C{H_3}) is correct because its oxidation leads to the formation of both acetic acid and propanoic acid via bond cleavage.

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