Skip to main content
Back to ELECTRIC POTENTIAL AND CAPACITANCE

JEE PHYSICS MCQ: ELECTRIC POTENTIAL AND CAPACITANCE

1 Medium
1 of 1
Application +4 | -1
A sample of HCl\mathrm{HCl} gas is placed in an electric field of 2.5×104 NC−12.5 \times 10^4 \mathrm{~N} \mathrm{C}^{-1}. The dipole moment of each HCl\mathrm{HCl} molecule is 3.4×10−30Cm3.4 \times 10^{-30} \mathrm{Cm}. Find the maximum torque that can act on a molecule.
View answer and explanation
Correct option: A
8.5×10−268.5 \times 10^{-26}
Option A (8.5×10−268.5 \times 10^{-26}) is correct because the maximum torque is calculated by multiplying the dipole moment and the electric field strength.

More Questions from ELECTRIC POTENTIAL AND CAPACITANCE

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.