Two resistance ${R_1}$ and ${R_2}$are made of different materials. The temperature coefficient of the material of ${R_1}$ is α and of the material of ${R_2}$ is $ - \beta $. The resistance of the series combination of ${R_1}$ and ${R_2}$ will not change with temperature, if ${R_1}/{R_2}$ equals

$\frac{{\alpha + \beta }}{{\alpha - \beta }}$

$\frac{{{\alpha ^2} + \,\,{\beta ^2}}}{{\alpha \beta }}$

JEE PHYSICS MCQ: CURRENT ELECTRICITY

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Two resistance

{R_1}

and

{R_2}

are made of different materials. The temperature coefficient of the material of

{R_1}

is α and of the material of

{R_2}

- \beta

. The resistance of the series combination of

{R_1}

and

{R_2}

will not change with temperature, if

{R_1}/{R_2}

equals

View answer and explanation

Correct option: D

\frac{\beta }{\alpha }

Option D (

\frac{\beta}{\alpha}

) is correct because the ratio of resistances must equal the inverse ratio of their temperature coefficients for the series combination to have a constant resistance.

JEE PHYSICS MCQ: CURRENT ELECTRICITY

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