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JEE MATHEMATICS MCQ: INCREASING & DECREASING

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Analyzing +4 | -1
Let f(x)=xex(1−x),x∈Rf(x)=x e^{x(1-x)}, x \in \mathbb{R} Then
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Correct option: A
f′(x)≥0f^{\prime}(x) \geq 0 in [−12,1]\left[\frac{-1}{2}, 1\right]
Option A (f′(x)≥0f^{\prime}(x) \geq 0 in [−12,1][\frac{{-1}}{{2}}, 1]) is correct because the derivative is non-negative in the given interval, as shown by the sign analysis of f′(x)f'(x).

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