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JEE MATHEMATICS MCQ: COMBINATIONS

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Application +4 | -1
On the sides AB,BC,CA\mathrm{AB}, \mathrm{BC}, \mathrm{CA} of a β–³ABC,3,4,5\triangle \mathrm{ABC}, 3,4,5 distinct points (excluding vertices A, B, C) are respectively chosen. The number of triangles that can be constructed using these chosen points as vertices are :
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Correct option: B
205
Option B (205) is correct because the total number of triangles that can be formed is calculated by subtracting the number of collinear points from the total possible combinations.

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