JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1

\log _2(a+b)+\log _2(c+d) \geq 4

. Then the min. value of the expression

a+b+c+d

View answer and explanation

Correct option: C

Option C (8) is correct because by applying AM-GM inequality, the minimum value of a+b+c+d is found to be 8.

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