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JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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The equation a  cos⁑  θ+b  sin⁑  θ=ca\,\,\cos \,\,\theta + b\,\,\sin \,\,\theta = c has a solution, when a,β€…β€Šβ€‰ba,\;\,b and cc are real numbers such that

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Correct option: C
c2≀a2+b2{c^2} \le {a^2} + {b^2}
Option C (c2≀a2+b2{c^2} \le {a^2} + {b^2}) is correct because the equation acos⁑θ+bsin⁑θ=ca\cos \theta + b\sin \theta = c has a solution only if cc lies within the range [βˆ’a2+b2,a2+b2][-\sqrt{a^2+b^2}, \sqrt{a^2+b^2}], which implies c2≀a2+b2{c^2} \le {a^2} + {b^2}.

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