A body travels $102.5 \mathrm{~m}$ in ${n}^{\text {th}}$ second and $115.0 \mathrm{~m}$ in $({n}+2)^{\mathrm{th}}$ second. The acceleration is:

$12.5 \mathrm{~m} / \mathrm{s}^2$

NEET UG PHYSICS MCQ: MOTION IN A STRAIGHT LINE

1 Hard

1 of 1

Application +4 | -1

A body travels

102.5 \mathrm{~m}

{n}^{\text {th}}

second and

115.0 \mathrm{~m}

({n}+2)^{\mathrm{th}}

second. The acceleration is:

View answer and explanation

Correct option: B

6.25 \mathrm{~m} / \mathrm{s}^2

Option B

6.25 \mathrm{~m} / \mathrm{s}^2

is correct because it is calculated using the formula for distance traveled in the nth second and solving the resulting equations.

Practice All Chapter MCQs →

8 \mathrm{~m} / \mathrm{s}

30\mathrm{km}{\mathrm{h}^{ - 1}}

1 \mathrm{~ms}^{-2}

150 \mathrm{~m}

2 \mathrm{~ms}^{-2}

{V_1} = 10\,kmph

{V_2} = 20\,kmph

{V_3} = 60\,kmph