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JEE MATHEMATICS MCQ: COMBINATIONS

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Analyzing +4 | -1
If (1+x)n=∑r=0narxr,br=1+arar−1(1+x)^n=\sum\limits_{{r=0}}^n a_r x^r, b_r=1+\frac{a_r}{a_{r-1}} and ∏r=1nbr=(101)100100!\prod\limits_{{r=1}}^n b_r=\frac{(101)^{100}}{100 !}, then value of nn is
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Correct option: B
100
Option B (100) is correct because the value of n is 100, derived from the given binomial expansion and product.

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