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JEE MATHEMATICS MCQ: STRAIGHT LINES

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Analyzing +4 | -1
If the point (p,5)(p, 5) lies on the line parallel to yy-axis and passing through the intersection of the lines 2(a2+1)x+by+4(a3+a)=02\left(a^2+1\right) x+b y+4\left(a^3+a\right)=0 and (a2+1)x−6by+2(a3+a)=0\left(a^2+1\right) x-6 b y+2\left(a^3+a\right)=0, then pp is equal to
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Correct option: B
−2a-2 a
Option B (−2a-2a) is correct because the x-coordinate of the intersection point of the given lines, which is parallel to the y-axis, is -2a.

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