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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1
Let a1,a2,…an,…a_1, a_2, \ldots a_n, \ldots be a G.P. of positive terms such that ∑n=1100a2n+1=200,∑n=1100a2n=100\sum\limits_{n=1}^{100} a_{2 n+1}=200, \sum\limits_{n=1}^{100} a_{2 n}=100. Then, ∑n=1200an\sum\limits_{n=1}^{200} a_n is equal to
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Correct option: B
150
Option B is correct because by using the given sums and the properties of a geometric progression, the sum of the first 200 terms can be found to be 150.

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