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JEE CHEMISTRY MCQ: d & f- BLOCK ELEMENTS

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Analyzing +4 | -1
When a certain compound XX (used in laboratory for analysis) is added to copper sulphate solution a yellow-brown precipitate is obtained which turns white on addition of excess of Na2 S2O3\mathrm{Na}_2 \mathrm{~S}_2 \mathrm{O}_3 solution.On addition to Ag+\mathrm{Ag}^{+}ion solution, a yellow curdy precipitate is obtained which is insoluble in NH4OH\mathrm{NH}_4 \mathrm{OH}. The XX is
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Correct option: C
KI\mathrm{KI}
Option C (KI) is correct because KI reacts with copper sulfate to form a yellow-brown precipitate that turns white with excess Na2S2O3, and it forms a yellow curdy precipitate with Ag+ that is insoluble in NH4OH.

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