Statement I: If '$a$' is the first term and '$d$' is the common difference of an A.P., then its $n^{\text {th }}$ term is given by $a_n=a-(n-1) d$ Statement II: The sum $S_n$ of $n$ terms of an A.P. with first term '$a$' and common difference '${d}$' is given by ${S}_{{n}}=\frac{{n}}{2}\{2 {a}+({n}-1) {d}\}.$ Choose the correct option.

JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

1 of 1

Understanding +4 | -1

Statement I: If '

a

' is the first term and '

d

' is the common difference of an A.P., then its

n^{\text {th }}

term is given by

a_n=a-(n-1) d

Statement II: The sum

S_n

n

terms of an A.P. with first term '

a

' and common difference '

{d}

' is given by

{S}_{{n}}=\frac{{n}}{2}\{2 {a}+({n}-1) {d}\}.

Choose the correct option.

View answer and explanation

Correct option: B

Only II is true

Option B (Only II is true) is correct because statement I has an incorrect sign, while statement II correctly states the sum of n terms of an A.P.