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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy
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Application +4 | -1
The value of 41/3⋅41/9⋅41/27…∞4^{1 / 3} \cdot 4^{1 / 9} \cdot 4^{1 / 27} \ldots \infty is
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Correct option: A
2
Option A (2) is correct because the expression can be simplified to 41/24^{1/2}, which equals 2.

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