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NEET UG CHEMISTRY MCQ: STRUCTURE OF ATOM

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If the radius of first Bohr orbit is ‘a’, then de Broglie wavelength off electron in 3rd orbit is nearly
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Correct option: B
6πa6\pi a
Option B (6πa6\pi a) is correct because the circumference of the 3rd Bohr orbit is 2πr=nλ2\pi r = n\lambda, and r=n2ar = n^2a, so 2π(9a)=3λ2\pi(9a) = 3\lambda, which gives λ=6πa\lambda = 6\pi a.

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