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JEE CHEMISTRY MCQ: SOME BASIC CONCEPTS OF CHEMISTRY

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Application +4 | -1
Chlorofluorocarbons such as CCl3F(M=137.5){CCl}_3 {F}(\mathrm{M}=137.5) and CCl2F2(M=121){CCl}_2 {F}_2(\mathrm{M}=121) have been linked to ozone depletion in Antarctica. As of 2004, these gases were found in 275 and 605 parts per trillion (1012),\left(10^{12}\right), by volume. What are the concentrations of these gases under conditions typical of Antarctica stratosphere (200 K(200 \mathrm{~K} and 0.08 atm)?(R=0.08 l-atm/K-mol)0.08 \mathrm{~atm}) ?(R=0.08 \, l \text{-atm/K-mol})
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Correct option: A
[CCl3F]=1.375×10−12 mol l−1,[CCl2F2]=3.025×10−12 mol l−1\left[{CCl}_3 {F}\right]=1.375 \times 10^{-12} \mathrm{~mol} \, {l}^{-1},\left[{CCl}_2 {F}_2\right]=3.025 \times 10^{-12} \mathrm{~mol} \, l^{-1}
Option A ([CCl3F]=1.375×10−12 mol,l−1,[CCl2F2]=3.025×10−12 mol,l−1\left[{CCl}_3 {F}\right]=1.375 \times 10^{-12} \mathrm{~mol} \\, {l}^{-1},\left[{CCl}_2 {F}_2\right]=3.025 \times 10^{-12} \mathrm{~mol} \\, l^{-1}) is correct because it correctly calculates the concentrations using the ideal gas law and the given parts per trillion values.

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