The ratio of two specific heats of gas ${C_p}/{C_v}$ for argon is ${\rm{1}}{\rm{.6}}$ and for hydrogen is ${\rm{1}}{\rm{.4}}$. Adiabatic elasticity of argon at pressure $P$ is $E$. Adiabatic elasticity of hydrogen will also be equal to $E$ at the pressure

JEE PHYSICS MCQ: MECHANICAL PROPERTIES OF SOLIDS

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The ratio of two specific heats of gas

{C_p}/{C_v}

for argon is

\mathrm{1}\mathrm{.6}

and for hydrogen is

\mathrm{1}\mathrm{.4}

. Adiabatic elasticity of argon at pressure

P

E

. Adiabatic elasticity of hydrogen will also be equal to

E

at the pressure

View answer and explanation

Correct option: B

\frac{8}{7}P

Option B (

\frac{8}{7}P

) is correct because it equates the adiabatic elasticity of argon and hydrogen, using the given ratio of specific heats to find the pressure at which their elasticities are equal.

More Questions from MECHANICAL PROPERTIES OF SOLIDS

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A wire is stretched under a force. If the wire suddenly snaps the temperature of the wire The increases in length is

l

of a wire of length

L

by the longitudinal stress. Then the stress is proportional to A steel wire of length

l

and cross sectional area

\mathrm{A}

is stretched by

1 \mathrm{~cm}

under a given load. When the same load is applied to another steel wire of double its length and half of its cross section area, the amount of stretching (extension) is Assertion: From the relation

Y=\frac{F l}{A \Delta l},

we can say that, if length of a wire is doubled, its Young's modulus of elasticity will also becomes two times.

Reason: Modulus of elasticity is a material property. A wire can be broken by applying a load of 200 N. The force required to break another wire of the same length and same material, but double in diameter, is Assertion(A): If radius of cylindrical wire is doubled, then this wire can bear four times stress.

Reason(R): By doubling the radius, area of cross-section will become four times.