JEE MATHEMATICS MCQ: ELLIPSE

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Application +4 | -1

The distance of the point '

\theta

' on the ellipse

\frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} = 1

from a focus is

View answer and explanation

Correct option: C

a\left( {1 + e\cos \theta } \right)

Option C,

a(1 + e\cos \theta)

, is correct because the focal distance is derived using the ellipse equation and the definition of eccentricity.

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