Back to DUAL NATURE OF RADIATION AND MATTER

NEET UG PHYSICS MCQ: DUAL NATURE OF RADIATION AND MATTER

1 Medium

1 of 1

Application +4 | -1

Find the de-Broglie wavelength for electrons which passed through a potential difference of 100 V ?

\left[ {h = 6.625 \times {{10}^{ - 34}}J - \sec } \right]

View answer and explanation

Correct option: A

1.228\mathop \mathrm{A}\limits^ \circ

Option A (

1.228\mathop \mathrm{A}\limits^ \circ

) is correct because it is calculated using the formula for de-Broglie wavelength:

\lambda = \frac{12.27}{\sqrt{V}} \mathop \mathrm{A}\limits^ \circ

.

More Questions from DUAL NATURE OF RADIATION AND MATTER

Practice All Chapter MCQs →

If the Broglie wavelengths associated with a proton and an

\alpha

- particle are equal, then the ratio of velocities of the proton and the

\alpha

- particle will be: If the wavelength of incident light changes from 400 nm to 300 nm, the stopping potential for photoelectrons emitted from a surface becomes approximately In photo-electric effect, when graph is plotted for stopping potential versus frequency of incident light, for different metals, then: The radiation corresponding to

3 \to 2

transition of hydrogen atom falls on a metal surface to produce photoelectrons. These electrons are made to enter a magnetic field of

3 \times {10^{ - 4}}\,T.

If the radius of the largest circular path followed by these electrons is 10.0 mm, the work function of the metal is close to The shortest wavelength of

X

-rays emitted from an

X

-ray tube depends on the Planck’s constant has the dimensions of