Oxidation number of ${H}$ in ${NaH}, {CaH}_2$ and ${LiH}$, respectively is

JEE CHEMISTRY MCQ: REDOX REACTIONS

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Understanding +4 | -1

Oxidation number of

{H}

{NaH}, {CaH}_2

and

{LiH}

, respectively is

View answer and explanation

Correct option: D

-1,-1,-1

Option D (-1, -1, -1) is correct because hydrogen bonded to a more electropositive metal has a -1 oxidation state.

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\mathrm{H}

2 \mathrm{KClO}_3 \longrightarrow 2 \mathrm{KCl}+3 \mathrm{O}_2

\mathrm{HNO}_3

\mathrm{HNO}_3

\mathrm{MnO}_4^{-}(\mathrm{aq})+\mathrm{Br}^{-}(\mathrm{aq})+\mathrm{H}_2 \mathrm{O} \longrightarrow 2 \mathrm{MnO}_2(\mathrm{aq})+\mathrm{BrO}_3^{-}(\mathrm{aq})+2 \mathrm{OH}^{-}(\mathrm{aq})

\mathrm{Br}

-1

+5.