If $e^x=y+\sqrt{1+y^2}$, then $y=$

JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

e^x=y+\sqrt{1+y^2}

, then

y=

View answer and explanation

Correct option: B

\frac{e^x-e^{-x}}{2}

Option B (

\frac{{e^x-e^{-x}}}{{2}}

) is correct because solving the given equation for

y

involves squaring and rearranging terms to isolate

y

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