JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

1 of 1

Application +4 | -1

The complex number

z=1+i

is rotated through an angle

3 \pi / 2

in anti-clockwise direction about the origin and stretched by additional

\sqrt{2}

units, then the new complex number is

View answer and explanation

Correct option: D

None of the above

The correct answer is None of the above because after rotation and stretching, the new complex number is 2 - 2i.

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{\left| {1 - i} \right|^x} = {2^x}

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z \neq \pm 1

z, \frac{z}{1-z^2}

\left|z_r-r\right| \leq r, \forall r=1,2,3, \ldots, n

\left|\sum\limits_{r=1}^n z_r\right|

(z+a b)^3=a^3

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\alpha, \beta

\gamma

|\alpha-\beta|

{z^2} + {\left| z \right|^2} = 0,

z \in C

2x = - 1 + \sqrt 3 i

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