JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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Analyzing +4 | -1

Which two of the following five physical parameters have the same dimensions?
(A) Energy density

(B) Refractive index
(C) Dielectric constant
(D) Young's modulus
(E) Magnetic field

View answer and explanation

Correct option: C

(A) and (D)

Option C ((A) and (D)) is correct because both energy density and Young's modulus have the same dimensions of

\mathrm{{ML}}^{-1} \mathrm{{T}}^{-2}

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Assertion :

\sqrt{\frac{\text { Modulus of elasticity }}{\text { Density }}}

has the unit

\mathrm{ms}^{-1} \text {. }

Reason: Acceleration has the dimensions of

\frac{1}{\left(\sqrt{\varepsilon_0 \mu_0}\right) t} \text {. }

The method of dimensional analysis can be used to derive which of the following relations? Statement-I: Dimensions of constant of proportionality of constants can be derived from dimensional method
Statement-II: Numerical value of constant of proportionality can be found from experiments only The dimensions of torque are The physical quantity having the dimensions

\left[ {{\mathrm{M}^{ - 1}}{\mathrm{L}^{ - 3}}{\mathrm{A}^2}{T^3}} \right]

is A quantity X is given by

{\varepsilon _0}L\frac{{\Delta V}}{{\Delta t}},\;

, where

{\varepsilon _0}

is the permittivity of free space, L is a length,

{\Delta V}

is a potential difference and

{\Delta t}

is a time interval. The dimensional formula for X is the same as that of