Breaking stress of a steel wire of radius $1 \mathrm{~mm}$ and length $1 \mathrm{~m}$ is $10^{12} \mathrm{~N} / \mathrm{m}^2$. Breaking stress of another steel wire of radius $2 \mathrm{~mm}$ and length $0.5 \mathrm{~m}$ will be

$4 \times 10^{12} \mathrm{~N} / \mathrm{m}^2$

$2.5 \times 10^{11} \mathrm{~N} / \mathrm{m}^2$

$2 \times 10^{12} \mathrm{~N} / \mathrm{m}^2$

JEE PHYSICS MCQ: MECHANICAL PROPERTIES OF SOLIDS

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Understanding +4 | -1

Breaking stress of a steel wire of radius

1 \mathrm{~mm}

and length

1 \mathrm{~m}

10^{12} \mathrm{~N} / \mathrm{m}^2

. Breaking stress of another steel wire of radius

2 \mathrm{~mm}

and length

0.5 \mathrm{~m}

will be

View answer and explanation

Correct option: B

10^{12} \mathrm{~N} / \mathrm{m}^2

10^{12} \mathrm{~N} / \mathrm{m}^2

is the correct answer because breaking stress is a material property and is independent of the dimensions of the wire.

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l

L

l

\mathrm{A}

1 \mathrm{~cm}

Y=\frac{F l}{A \Delta l},