NEET UG CHEMISTRY MCQ: CO-ORDINATION COMPOUNDS

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The hybridization of central metal ion and shape of Wilkinson’s catalyst is

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Correct option: C

ds{p^2},

squre planar

Option C (

ds{p^2},

squre planar) is correct because Wilkinson's catalyst,

[RhCl(PPh_3)_3]

, has Rh in a +1 oxidation state, leading to a

d^8

configuration and

ds{p^2}

hybridization, resulting in a square planar geometry.

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\left[ {\mathrm{PtC}{\mathrm{l}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{B}{\mathrm{r}_2}\mathrm{\;and\;}\left[ {\mathrm{PtB}{\mathrm{r}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{C}{\mathrm{l}_2}\mathrm{\;}

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