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JEE MATHEMATICS MCQ: STATISTICS

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If xˉ1\bar{x}_1 and σ1\sigma_1 are the mean and standard deviation of the first distribution and xˉ2\bar{x}_2 and σ2\sigma_2 are the mean and standard deviation of the second distribution.

I. CV (1st distribution)=σ1x‾1×100=\frac{\sigma_1}{\overline{{x}}_1} \times 100

II. CV (2nd distribution)=x‾2σ2×100=\frac{\overline{{x}}_2}{\sigma_2} \times 100

III. For x‾1=x‾2\overline{{x}}_1=\overline{{x}}_2, the series with lesser value of standard deviation is said to be more variable than the other.

IV. For x‾1=x‾2\overline{{x}}_1=\overline{{x}}_2, the series with greater value of standard deviation is said to be more consistent than the other.
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Correct option: A
Only I is true
Option A (Only I is true) is correct because the coefficient of variation (CV) for the first distribution is indeed calculated as the standard deviation divided by the mean, multiplied by 100.

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