If $f(x)=x^2 \sin \frac{1}{x}$, where $x \neq 0$, then the value of the function ${f}$ at ${x}=0$, so that the function is continuous at $x=0$, is

JEE MATHEMATICS MCQ: LIMITS

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Understanding +4 | -1

f(x)=x^2 \sin \frac{1}{x}

, where

x \neq 0

, then the value of the function

{f}

{x}=0

, so that the function is continuous at

x=0

, is

View answer and explanation

Correct option: A

Option A is correct because the limit of the function as x approaches 0 is 0, making the function continuous at x=0 if f(0)=0.

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