JEE PHYSICS MCQ: SYSTEM OF PARTICLES

1 Medium

1 of 1

Analyzing +4 | -1

Two spheres, one solid and another hollow are made up of same material and are of same radius. Both the spheres are heated to same temperature

\mathrm{T}_0

. Now, both spheres are left to cool in an atmosphere having temperature

\mathrm{T_A}\left(\mathrm{T_A \ll T_0}\right)

. After time

\mathrm{t}

the temperature of sphere becomes

\mathrm{T}_1

and that of hollow sphere becomes

\mathrm{T}_2

. Then,

View answer and explanation

Correct option: C

\mathrm{T}_1 > \mathrm{T}_2

Option C (

\mathrm{T}_1 > \mathrm{T}_2

) is correct because the solid sphere has a greater mass than the hollow sphere, leading to a slower rate of cooling according to Newton's law of cooling.

More Questions from SYSTEM OF PARTICLES

Practice All Chapter MCQs →

It is easier for a swimmer jumping into water from a height to describe a loop in the air by A uniform thin rod

\mathrm{AB}

of length

\mathrm{L}

has linear mass density

\mu(x)=a+\frac{b x}{L}

, where

x

is measured from

\mathrm{A}

. If the

\mathrm{CM}

of the rod lies at a distance of

\left(\frac{7}{12}\right) \mathrm{L}

from

\mathrm{A}

, then a and

\mathrm{b}

1.0 \mathrm{~g}

is rotating in a circle of diameter

8 \mathrm{~cm}

. Its moment of inertia will be The angular velocity of a particle is given by

\omega = {t^4} + 2{t^3}

then its angular acceleration of the particle at

t = 1\,sec

\left( {rad\,{s^{ - 2}}} \right)