JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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Analyzing +4 | -1

The equation of state of a real gas is given by

\left(P+\frac{a}{V^2}\right)(V-b)=R T,

where

P, V

and

T

are pressure, volume and temperature respectively and

R

is the universal gas constant. The dimensions of

\frac{a}{b^2}

is similar to that of:

View answer and explanation

Correct option: A

P

Option A (

P

) is correct because dimensional analysis shows that the dimensions of

\frac{a}{b^2}

are the same as pressure.

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