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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Let the sum of the first n\mathrm{n} terms of a non-constant A.P., a1,a2,a3,…\mathrm{a}_1, \mathrm{a}_2, \mathrm{a}_3, \ldots. be 50n+n(n−7)2 A50 \mathrm{n}+\frac{\mathrm{n}(\mathrm{n}-7)}{2} \mathrm{~A}, where A\mathrm{A} is a constant. If d\mathrm{d} is the common difference of this A.P., then the ordered pair (d,a50)\left(\mathrm{d}, \mathrm{a}_{50}\right) is equal to
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Correct option: A
(A,50+46 A)(\mathrm{A}, 50+46 \mathrm{~A})
Option A ((A, 50+46A)) is correct because the common difference and the 50th term of the A.P. are calculated using the given sum of the first n terms.

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