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JEE PHYSICS MCQ: OSCILLATIONS

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Application +4 | -1

A particle performs linear S.H.M. At a particular instant, velocity of the particle is '

u

' and acceleration is '

\alpha

' while at another instant velocity is '

v

' and acceleration is '

\beta

'

(0<\alpha<\beta)

. The distance between the two positions is

View answer and explanation

Correct option: A

\frac{u^2-v^2}{\alpha+\beta}

Option A (

\frac{u^2-v^2}{\alpha+\beta}

) is correct because it is derived from the equations of SHM relating velocity, acceleration, and displacement.

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{y_2}

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