JEE CHEMISTRY MCQ: REDOX REACTIONS

1 Easy

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Analyzing +4 | -1

Statement-I:

{{\text{S}}_2}{\text{O}}_3^{2 - }\left( {{\text{aq}}} \right) + 2{{\text{H}}^ + }\left( {{\text{aq}}} \right) \to {{\text{H}}_2}{\text{O}}\left( l \right) + {\text{S}}{{\text{O}}_2} + {{\text{S}}_{\left(\text{s} \right)\,\,{\text{collid}}}}

is a redox reaction.

Statement-II: Sulphur in

-2

oxidation state in

\mathrm{S}_2 \mathrm{O}_3{ }^{2-}

precipitates as colloidal sulphur.

View answer and explanation

Correct option: A

Both the statements are correct

Option A (Both the statements are correct) is correct because the reaction involves both oxidation and reduction, and sulfur in

{{\text{S}}_2}{\text{O}}_3^{2 - }

does form colloidal sulfur.

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