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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Analyzing +4 | -1
If f(n)=1n{(n+1)(n+2)(n+3)…(n+n)}1/nf(n)=\frac{1}{n}\{(n+1)(n+2)(n+3) \ldots(n+n)\}^{1 / n}, then lim⁡n→∞f(n)\lim \limits_{{n \rightarrow \infty}} f(n) equals
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Correct option: D
4/e4 / e
Option A (less than 10−710^{-7}) is correct because the integral's absolute value is less than 10−710^{-7} due to the small magnitude of the integrand over the given interval.

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