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NEET UG PHYSICS MCQ: MOTION IN PLANE

1 Easy

1 of 1

Application +4 | -1

If

\frac{1}{{\sqrt 3 }}\left| {\vec a \times \vec b} \right| = \overrightarrow a \cdot \overrightarrow b

then angle between

\overrightarrow a

and

\overrightarrow b

is

View answer and explanation

Correct option: B

60^\circ

Option B (

60^\circ

) is correct because when

\frac{1}{{\sqrt 3 }}|{\vec a \times \vec b}| = \overrightarrow a \cdot \overrightarrow b

, it implies that

\tan \theta = \frac{1}{{\sqrt 3 }}

, which means

\theta = 60^\circ

.

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