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JEE PHYSICS MCQ: ELECTRIC POTENTIAL AND CAPACITANCE

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When charge of magnitude 10μC10 \mu \mathrm{C} is shifted from infinity to a point in an electric field, then it was found that work done by electrostatic forces is −10μJ-10 \mu \mathrm{J}. If this charge is doubled and moved again from infinity to the same point without changing its velocity, then find out the work done by electric field and against this electric field.
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Correct option: A
20μJ20 \mu \mathrm{J} ,−20μJ-20 \mu \mathrm{J}
Option A (20μJ20 \mu \mathrm{J} ,−20μJ-20 \mu \mathrm{J}) is correct because the work done is directly proportional to the charge moved in the electric field.

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