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JEE PHYSICS MCQ: WAVES

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Application +4 | -1
The number of beats produced per second by two vibrations: x1=x0sin⁡  646  πt{x_1} = {x_0}\sin \,\,646\,\,\pi t and x2=x0sin⁡  652  πt{x_2} = {x_0}\sin \,\,652\,\,\pi t is
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Correct option: B
33
Option B (3) is correct because the beat frequency is the absolute difference between the frequencies of the two vibrations.

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