NEET UG CHEMISTRY MCQ: STRUCTURE OF ATOM

1 Easy

1 of 1

Application +4 | -1

Calculate the number of a and particles in the following change.

{ }_{92}^{235} \mathrm{U} \rightarrow \frac{{207}}{{{\text{a}}2}}{\text{Pb}}

View answer and explanation

Correct option: D

7

4

Option D (7, 4) is correct because the change in mass number is 235-207 = 28, and each alpha particle emission reduces the mass number by 4, so 28/4 = 7 alpha particles are emitted. The change in atomic number is 92-82 = 10, and each alpha particle reduces the atomic number by 2, and each beta particle increases the atomic number by 1. Thus, 10 = 7*2 - x*(-1) => x = 4.

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