JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1

1^2+2^2+3^2+\ldots+2003^2=(2003)(4007)(334)

and

(1)(2003)+(2)(2002)+(3)(2001)

+\ldots+(2003)(1)=(2003)(334)(x)

then

x

equals

View answer and explanation

Correct option: A

2005

Option A (2005) is correct because by adding the two given series and simplifying, we can solve for x and find that x = 2005.

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