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JEE MATHEMATICS MCQ: TRANSFORMATIONS

1 Easy

1 of 1

Application +4 | -1

The minimum value of

\cos \,\,2\theta + \cos \,\,\theta

for real values of

\theta

, is

View answer and explanation

Correct option: A

- \,9/8

Option A (

- \,9/8

) is correct because the minimum value of

\cos \,2\theta + \cos \theta

is

- \,9/8

when

\theta

is a real number.

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1 + \cos \,\,56^\circ + \cos \,\,58^\circ - \cos \,\,66^\circ = \lambda \cos \,\,28^\circ \,\,\cos \,\,29^\circ \,\,\sin \,\,33^\circ

\lambda =

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\;\cos \,\,x + \cos \,\,y + \cos \,\,\alpha = 0\;\,\mathrm{and}\,\sin x + \sin \,\,y + \sin \,\,\alpha = 0

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f\left( x \right) = \sin \left( {\frac{{2x + 3}}{{6\;\pi }}} \right),

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