NEET UG PHYSICS MCQ: MOTION IN PLANE

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Analyzing +4 | -1

A particle moves in XY-plane with

x

and

y

varying with time

t

x(t)=5 t, y(t)=5 t(27-

\left.t^2\right)

. At what time in seconds, the direction of velocity and acceleration will be perpendicular to each other?

View answer and explanation

Correct option: D

3

Option D (3) is correct because the velocity and acceleration vectors are perpendicular when their dot product is zero, which occurs at t=3s.

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\mathrm{\vec a}\,and\,\mathrm{\vec b}

\mathrm{\vec a}\,and\,\mathrm{\vec b}

\overrightarrow P \,\,.\,\,\overrightarrow Q = 0\,and\,\overrightarrow P \,\, \times \,\,\overrightarrow Q = 0

\overrightarrow Q \,and\,\overrightarrow R

\vec{A}=3 \hat{i}+4 \hat{j}

\vec{B}=6 \hat{i}+8 \hat{j}

A

B

\overrightarrow{\mathrm{A}}

\overrightarrow{\mathrm{B}}

{\cot ^{ - 1}}\left( 2 \right)