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JEE PHYSICS MCQ: MOTION IN A STRAIGHT LINE

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A train accelerates from rest at a constant rate α for distance x1{x_1} and time t1{t_1}. After that it retards to rest at constant rate β\beta for distance x2{x_2} and time t2{t_2}. Then it is found that
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Correct option: B
x1x2=βα=t1t2\frac{{{x_1}}}{{{x_2}}} = \frac{\beta }{\alpha } = \frac{{{t_1}}}{{{t_2}}}
Option C is correct because the ratio of distances is equal to the inverse ratio of accelerations, and the ratio of times is also equal to the inverse ratio of accelerations.

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