JEE MATHEMATICS MCQ: TRANSFORMATION OF AXES

1 Easy

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Application +4 | -1

The angle through which the coordinates axes be rotated so that

x y

-term in the equation

5 x^2+4 \sqrt{3} x y+9 y^2=0

may be missing, is

View answer and explanation

Correct option: C

\pi / 3

Option C (

\pi / 3

) is correct because it is the angle that eliminates the

xy

term when the axes are rotated, as found by solving the equation

\tan 2\theta = \frac{2h}{a-b}

More Questions from TRANSFORMATION OF AXES

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12 x^2+7 x y-12 y^2-17 x-31 y-7=0,

3 x+4 y-5=0

xy

5{x^2} + 4\sqrt 3 \;xy + 9{y^2} - 8 = 0

\alpha=\ldots \ldots

x \cos \alpha+y \sin \alpha=p

p \neq 0

\sqrt{3}

(a b /(a-b), 0)

(a-b)\left(x^2+y^2\right)-2 a b x-0

y^2+4 y+8 x-2=0

y