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JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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In a Δ ABC\Delta \,ABC, if a=8,  b=10a = 8,\,\,b = 10 and c=12c = 12, then CC is equal to
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Correct option: B
2A2A
Option B (2A2A) is correct because by using the Law of Cosines, we find that cos⁡C=18\cos C = \frac{1}{8} and cos⁡2A=18\cos 2A = \frac{1}{8}, thus C=2AC = 2A.

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