JEE MATHEMATICS MCQ: ELLIPSE

1 Easy

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Application +4 | -1

The locus of the foot of the perpendicular drawn from the centre of the ellipse

\frac{x^2}{a^2}+\frac{y^2}{b^2}=1

on any tangent, is

View answer and explanation

Correct option: C

\left(x^2+y^2\right)^2=a^2 x^2+b^2 y^2

Option C (

(x^2+y^2)^2=a^2 x^2+b^2 y^2

) is correct because it represents the locus of the foot of the perpendicular from the center of the ellipse on any tangent.

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